How do you find the equation of the derivative for this function?

The equation is f(x)=1/(x-2) and I am having trouble using the difference quotient to find the equation for the derivative (the equation that you can use to put in any value for x and find the instantaneous rate of change at that time). To refresh your memory, the difference quotient is [f(x+h)-f(x)] / h How do you find the equation of the derivative for this function?
No need to use the quotient rule my good chum. Rewrite the equation as:



f(x) = (x-2)^-1, then use the chain rule. So the final answer is:



-(x-2)^-2 * 1, or:



-1/(x-2)^2



Hope this helps.How do you find the equation of the derivative for this function?
Don't think of f(x) as a fraction, think of it like this:



f(x) = (x-2)^(-1) (x minus 2 to the negative 1)



so: f'(x) = -(x-2)^(-2)

following the rule:



x^n = nx^(n-1)